Engineer/Mathematician/Student. I’m not insane unless I’m in a schizoposting or distressing memes mood; I promise.

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Joined 1 year ago
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Cake day: July 28th, 2023

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  • hihi24522@lemm.eetomemes@lemmy.worldIt's true.
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    14 days ago

    Well actually it’s the other way around. The reason imaginary numbers were invented was to solve a problem we’d been crying over for centuries.

    Then, as in most cases, solving one problem opens the door to millions of other problems like why in the fuck does the universe use these imaginary numbers we made up to solve cube roots?

    Why is i a core part of the unit circle with like ei*pi ? “Oh that’s because i is just perpendicular to the real number line” ?! Say that sentence again, how the fuck did we go from throwing sharp sticks to utterly deranged sentences like that? More importantly why do utterly deranged sentences like that accurately describe our universe and what is the next ludicrous math concept we’re going to discover is integral to the function of the universe?




  • Wait. I just realized energy also creates a gravitational pull, and the death star’s whole thing is destroying a planet right? That’s got to take a huuuge amount of energy because the explosion has to massively overcome the gravity holding the target together.

    A quick google search says you’d need 10^32 Joules to blow up the earth. E=mc2 so dividing that energy by the speed of light squared gives about 1.1e15 kg of equivalent mass which is relatively small compared to earths mass (6e24) but still large.

    For reference, if the radius of the Death Star was 1000m you’d get about 5.2m/s2 acceleration from just that energy in its core.

    But if the Death Star is able to blow up multiple planets, then the energy it has to have on hand goes up. So if the Death Star contains enough energy to blow up 5.4 billion planets, then just that stored energy would have nearly equivalent “mass” to the earth.

    But gravitational acceleration is inversely proportional to distance squared. So since the Death Star is small, you wouldn’t need that much energy to get earth gravity. If we assume the Death Star has about a 160km radius, then you’d only need enough stored energy to blow up ~45,000 earths to get a surface gravity of 9.1m/s2.

    This gravity would increase as you got closer to the core or whatever part stores all that energy. But if you spread that energy out a bit you could probably extend how large the earth-like gravity range in the station would be.

    The mass of the structure itself would contribute to the gravity too so that 45,000 is probably an overestimate.

    TL;DR: From rough math in my head, assuming a radius of 160km, point mass, and ignoring the mass of the structure, you’d only need to store ~5e19 J of energy in the Death Star to get earth like gravity on the surface. That is approximately the amount of energy required to blow up 45,000 earths